Relationship between Gibbs Free Energy and Equilibrium Constant Calculator
This equation establishes the thermodynamic link between the standard Gibbs free energy change and the equilibrium constant of a chemical reaction.
Formula first
Overview
The equation shows that the spontaneity of a reaction under standard conditions is directly related to the position of its equilibrium. A negative Gibbs free energy value results in an equilibrium constant greater than one, indicating that the products are favored at equilibrium. Conversely, a positive Gibbs free energy value implies that the reactants are favored.
Symbols
Variables
G^ = Standard Gibbs Free Energy change (J/mol), R = Gas Constant (J/mol·K), T = Temperature (K), K = Equilibrium Constant
Apply it well
When To Use
When to use: Use this equation when you need to calculate the equilibrium constant from standard thermodynamic data or vice versa.
Why it matters: It allows chemists to predict the extent of a chemical reaction without having to measure concentrations experimentally at equilibrium.
Avoid these traps
Common Mistakes
- Forgetting to convert kiloJoules (kJ) to Joules (J) when performing calculations.
- Using the wrong temperature units (Celsius instead of Kelvin).
- Confusing the standard Gibbs free energy (ΔG°) with non-standard Gibbs free energy (ΔG).
One free problem
Practice Problem
Calculate the equilibrium constant K for a reaction at 298 K where ΔG° = -5.70 kJ/mol. (R = 8.314 J/mol·K)
Solve for:
Hint: Rearrange to K = e^(-ΔG / RT). Ensure ΔG is in Joules.
The full worked solution stays in the interactive walkthrough.
References
Sources
- Atkins, P., & de Paula, J. (2014). Physical Chemistry (10th ed.). Oxford University Press.
- Zumdahl, S. S., & Zumdahl, S. A. (2017). Chemistry (10th ed.). Cengage Learning.
- Atkins, P., & de Paula, J. (2014). Physical Chemistry, 10th Edition.
- Royal Society of Chemistry, A-Level Chemistry Resources.
- A-Level Chemistry (OCR/AQA/Edexcel Specification - Thermodynamics section)